document.write( "Question 1153985: An investment of ​$70 comma 000 was made by a business club. The investment was split into three parts and lasted for one year. The first part of the investment earned​ 8% interest, the second​ 6%, and the third​ 9%. Total interest from the investments was $ 5220. The interest from the first investment was 2 times the interest from the second. Find the amounts of the three parts of the investment.\r
\n" ); document.write( "\n" ); document.write( "The first part of the investment was ​$\r
\n" ); document.write( "\n" ); document.write( "2nd part $\r
\n" ); document.write( "\n" ); document.write( "Third part $
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Algebra.Com's Answer #776364 by mananth(16946)\"\" \"About 
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Let Investment I be x @8%
\n" ); document.write( "Investment II be y @ 6%
\n" ); document.write( "and investment III be z @ 9%\r
\n" ); document.write( "\n" ); document.write( "Total investment \r
\n" ); document.write( "\n" ); document.write( "x+y+z=70000-----------1\r
\n" ); document.write( "\n" ); document.write( "Interest accrued\r
\n" ); document.write( "\n" ); document.write( "8%x+6%y+9%z = 5220
\n" ); document.write( "multiply by 100\r
\n" ); document.write( "\n" ); document.write( "we get
\n" ); document.write( "8x+6y+9z =522000-------2\r
\n" ); document.write( "\n" ); document.write( "8%x = 2*6%y
\n" ); document.write( "therefore 8x=12y\r
\n" ); document.write( "\n" ); document.write( "8x-12y=0 -------3\r
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\n" ); document.write( " x + y + z = 70000
\n" ); document.write( "8 x + 6 y + 9 z = 522000
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\n" ); document.write( "8 x -12 y = 0
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\n" ); document.write( "consider equation 1 &2 Eliminate y
\n" ); document.write( "Multiply 1 by -6
\n" ); document.write( "Multiply 2 by 1
\n" ); document.write( "we get
\n" ); document.write( "-6 x -6 y -6 z = -420000
\n" ); document.write( "8 x + 6 y + 9 z = 522000
\n" ); document.write( "Add the two
\n" ); document.write( "2 x +3z = 102000 -------------4
\n" ); document.write( "consider equation 2 & 3 Eliminate y
\n" ); document.write( "Multiply 2 by 2
\n" ); document.write( "Multiply 3 by 1
\n" ); document.write( "we get
\n" ); document.write( "16 x + 12 y + 18 z = 1044000
\n" ); document.write( "8 x + -12 y = 0
\n" ); document.write( "Add the two
\n" ); document.write( "24 x +18z = 1044000 -------------5
\n" ); document.write( "Consider (4) & (5) Eliminate x
\n" ); document.write( "Multiply 4 by -12
\n" ); document.write( "Multiply (5) by 1
\n" ); document.write( "we get 2
\n" ); document.write( "-24 x -36 z = -1224000
\n" ); document.write( "24 x + 18 z = 1044000
\n" ); document.write( "Add the two
\n" ); document.write( " -18 z = -180000
\n" ); document.write( "
\n" ); document.write( "z = 10000
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\n" ); document.write( "Plug the value of z in (5)
\n" ); document.write( "24 x + 180000 = 1044000
\n" ); document.write( "24 x = 864000
\n" ); document.write( "x = 36000
\n" ); document.write( "plug value of x & z in 1
\n" ); document.write( "36000 + 1 y + 10000 = 70000
\n" ); document.write( " y = 70000 -36000 -10000
\n" ); document.write( " y= 24000 \r
\n" ); document.write( "\n" ); document.write( "First investment $36000
\n" ); document.write( "II investment $24000
\n" ); document.write( "III investment $10000\r
\n" ); document.write( "\n" ); document.write( "Total $70,000\r
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