document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106669>Question 106669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 6x + 4(3x – 2) = 6x + 2  \r<BR>\n" );
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document.write( "I am getting x=10  but I was not sure if I did it right. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77634 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77634\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve for x: If you are not sure that your solution is correct, be sure to substitute your solution back into the original equation to see if the two sides are equal. When you try this with x = 10 you'll find that it does not work!<BR>\n" );
document.write( "6x+4(3x-2) = 6x+2 Simplify the left side.<BR>\n" );
document.write( "6x+12x-8 = 6x+2  Subtract 6x from both sides.<BR>\n" );
document.write( "12x-8 = 2 Add 8 to both sides.<BR>\n" );
document.write( "12x = 10 Divide both sides by 12.<BR>\n" );
document.write( "x = 10/12 Reduce.<BR>\n" );
document.write( "x = 5/6<BR>\n" );
document.write( "Check: Substitute x = 5/6 into the original equation:<BR>\n" );
document.write( "6(5/6)+4(3(5/6)-2) = 6(5/6)+2 Simplify.<BR>\n" );
document.write( "5+4((5/2)-2) = 5+2<BR>\n" );
document.write( "5+4(1/2) = 7<BR>\n" );
document.write( "5+2 = 7<BR>\n" );
document.write( "7 = 7 </SPAN>\n" );
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