document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=106666>Question 106666</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0395977223/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> a messenger left a construction site and traveled by jeep at 51 km/h.  Forty minutes later it was discovered that she had been given the wrong parcel.  How fast must a second messenger travel to overtake her in one hour </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #77633 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=77633\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a messenger left a construction site and traveled by jeep at 51 km/h.  Forty minutes later it was discovered that she had been given the wrong parcel.  How fast must a second messenger travel to overtake her in one hour<BR>\n" );
document.write( "--------------------<BR>\n" );
document.write( "1st Messenger DATA:<BR>\n" );
document.write( "Rate = 51 kph ; Time = 1 hr 40 min = (5/3) hrs.; distance = rt = 85 km\r<BR>\n" );
document.write( "\n" );
document.write( "-----------------<BR>\n" );
document.write( "2nd Messenger  DATA:<BR>\n" );
document.write( "Time = 1 hr ; distance = 85 km ; Rate = d/t = 85 kph<BR>\n" );
document.write( "============<BR>\n" );
document.write( "1st Messenger DATA:<BR>\n" );
document.write( "Rate = 51 kph ; time = x hrs ; distance = 51x km<BR>\n" );
document.write( "----------------<BR>\n" );
document.write( "2nd Messenger DATA:<BR>\n" );
document.write( "Time = x-(2/3) hr ; distance = 51x km ; Rate = 51x/(x-(2/3)) kph<BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "EQUATIONS:<BR>\n" );
document.write( "x-(2/3) = 1 hr<BR>\n" );
document.write( "x = 5/3 hr<BR>\n" );
document.write( "================<BR>\n" );
document.write( "2nd Messenger Rate = (51(5/3))/((5/3)-(2/3)) =  = 85/1 = 85 kph<BR>\n" );
document.write( "=====================<BR>\n" );
document.write( "An easier way to do this is to see that the 1st messenger is driving <BR>\n" );
document.write( "51 kph for 1 hr 40 min or (5/3) hr which makes his distance = 85 km<BR>\n" );
document.write( "So the 2nd Messenger must cover 85 miles in 1 hr or 85 kph.<BR>\n" );
document.write( "==================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );