document.write( "Question 106672: One number is 4 less than another. If 10 times the smaller number minus 3 times the larger number is 51, find the two numbers.\r
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document.write( "So is this x(x-4)=51 I am lost\r
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document.write( "Thanks \n" );
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Algebra.Com's Answer #77629 by rcmcc(152) You can put this solution on YOUR website! Word problems are tricky to understand. The easiest way to derive an equation is to go step by step.\r \n" ); document.write( "\n" ); document.write( "the first equation you can find is simple.\r \n" ); document.write( "\n" ); document.write( "y=x-4\r \n" ); document.write( "\n" ); document.write( "where x is the larger number and y is the smaller one\r \n" ); document.write( "\n" ); document.write( "so if y is the smaller number 10x y subtracting 3x the larger number x looks like this\r \n" ); document.write( "\n" ); document.write( "10y-3x=51\r \n" ); document.write( "\n" ); document.write( "so your two equations are below\r \n" ); document.write( "\n" ); document.write( "y=x-4 \n" ); document.write( "10y-3x=51\r \n" ); document.write( "\n" ); document.write( "because you have y isolated you can substitute it in for the second equation\r \n" ); document.write( "\n" ); document.write( "10y-3x=51 \n" ); document.write( "10(x-4)-3x=51\r \n" ); document.write( "\n" ); document.write( "expand the brackets\r \n" ); document.write( "\n" ); document.write( "10x-40-3x=51\r \n" ); document.write( "\n" ); document.write( "simplify\r \n" ); document.write( "\n" ); document.write( "7x-40=51\r \n" ); document.write( "\n" ); document.write( "bring the 40 to the other side\r \n" ); document.write( "\n" ); document.write( "7x=91 \n" ); document.write( "divide by 7\r \n" ); document.write( "\n" ); document.write( "x=13\r \n" ); document.write( "\n" ); document.write( "because you have the larger number subtract 4 to find the smaller number\r \n" ); document.write( "\n" ); document.write( "your two numbers are (13 and 9) \n" ); document.write( " \n" ); document.write( " |