document.write( "Question 1153890: Two investments totaling $15,500 produce an annual income of $1450. One investment yields 10% per year, while the other yields 5% per year. How much is invested at each rate? \n" ); document.write( "

Algebra.Com's Answer #776214 by VFBundy(438) $\"\"$ $\"About$

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10% rate:
\n" ); document.write( "Principal = p
\n" ); document.write( "Rate = 0.10
\n" ); document.write( "Interest = 0.10p
\n" ); document.write( "
\n" ); document.write( "5% rate:
\n" ); document.write( "Principal = 15500 - p
\n" ); document.write( "Rate = 0.05
\n" ); document.write( "Interest = 0.05(15500 - p) = 775 - 0.05p
\n" ); document.write( "
\n" ); document.write( "0.10p + (775 - 0.05p) = 1450
\n" ); document.write( "
\n" ); document.write( "0.05p + 775 = 1450
\n" ); document.write( "
\n" ); document.write( "0.05p = 675
\n" ); document.write( "
\n" ); document.write( "p = 13500
\n" ); document.write( "
\n" ); document.write( "10% rate:
\n" ); document.write( "Principal = p = $13,500
\n" ); document.write( "
\n" ); document.write( "5% rate:
\n" ); document.write( "Principal = 15500 - p = 15500 - 13500 = $2000 \n" ); document.write( "

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