document.write( "Question 1153880: Find the equation of the circle with center at (6,3) and passes through the point (-6,-1) \n" ); document.write( "

Algebra.Com's Answer #776196 by greenestamps(13200) $\"\"$ $\"About$

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\n" ); document.write( " $\"%28x-h%29%5E2%2B%28y-k%29%5E2+=+r%5E2\"$ <---> center (h,k), radius r

\n" ); document.write( "Example: center (3,-2) and radius 5 --> $\"%28x-3%29%5E2%2B%28y%2B2%29%5E2+=+25\"$

\n" ); document.write( "Example: $\"%28x%2B1%29%5E2%2B%28y-4%29%5E2+=+16\"$ --> center (-1,4), radius 4

\n" ); document.write( "You are given the center (h,k).

\n" ); document.write( "The radius r is the distance from the center to the other given point. Use the distance formula (AKA Pythagorean Theorem) to determine r.

\n" ); document.write( "Then plug your h, k, and r in the formula.

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