document.write( "Question 1153880: Find the equation of the circle with center at (6,3) and passes through the point (-6,-1) \n" ); document.write( "
Algebra.Com's Answer #776192 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
\"%28x-6%29%5E2%2B%28y-3%29%5E2=%28-6-6%29%5E2%2B%28-1-3%29%5E2\"\r
\n" ); document.write( "\n" ); document.write( "Do what you can from that.\r
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\n" ); document.write( "\n" ); document.write( "---MORE DETAIL----\r
\n" ); document.write( "\n" ); document.write( "Basic equation for circle in coordinate plane: \"%28x-h%29%5E2%2B%28y-k%29%5E2=r%5E2\"\r
\n" ); document.write( "\n" ); document.write( "r is the radius.
\n" ); document.write( "point (h,k) is center point of circle.\r
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\n" ); document.write( "\n" ); document.write( "Your given center is (6,3).
\n" ); document.write( "Point on circle is given as (-6,-1).\r
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\n" ); document.write( "\n" ); document.write( "Left member of equation you want is \"%28x-6%29%5E2%2B%28y-3%29%5E2\".
\n" ); document.write( "Use the given point ON the circle to find the value of \"r%5E2\", the right member of the equation.\r
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\n" ); document.write( "\n" ); document.write( "\"%28x-6%29%5E2%2B%28y-3%29%5E2=%28-6-6%29%5E2%2B%28-1-3%29%5E2\"
\n" ); document.write( "AND DO THE NECESSARY COMPUTATION to get this value for \"r%5E2\";
\n" ); document.write( "\"%28-12%29%5E2%2B%28-4%29%5E2\"
\n" ); document.write( "\"144%2B16\"
\n" ); document.write( "\"160\"\r
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\n" ); document.write( "\n" ); document.write( "Finished equation is \"highlight%28%28x-6%29%5E2%2B%28y-3%29%5E2=160%29\".
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