document.write( "Question 1153880: Find the equation of the circle with center at (6,3) and passes through the point (-6,-1) \n" ); document.write( "
Algebra.Com's Answer #776192 by josgarithmetic(39618)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "\n" ); document.write( "Do what you can from that.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "---MORE DETAIL----\r \n" ); document.write( "\n" ); document.write( "Basic equation for circle in coordinate plane: \n" ); document.write( "\n" ); document.write( "r is the radius. \n" ); document.write( "point (h,k) is center point of circle.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your given center is (6,3). \n" ); document.write( "Point on circle is given as (-6,-1).\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Left member of equation you want is \n" ); document.write( "Use the given point ON the circle to find the value of \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "AND DO THE NECESSARY COMPUTATION to get this value for \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Finished equation is |