document.write( "Question 1153818: A box contains 9 balls marked 1 to 9. Four balls are drawn in succession
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Algebra.Com's Answer #776132 by Edwin McCravy(20060)\"\" \"About 
You can put this solution on YOUR website!
A box contains 9 balls marked 1 to 9. Four balls are drawn in succession
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document.write( "The 4-digit number is even when the last digit is even. i.e., 2,4,6, or 8.\r\n" );
document.write( "That's 4 ways the last digit could be OUT OF 9 possible ways.\r\n" );
document.write( "\"OUT OF\" means \"OVER\" so 4 OUT OF 9 means a probability of 4/9.

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document.write( "The 4-digit number is greater than 5000 when the first digit is 5,6,7,8 or 9.\r\n" );
document.write( "That's 5 ways the first digit could be OUT OF 9 possible ways.\r\n" );
document.write( "\"OUT OF\" means \"OVER\" so 5 OUT OF 9 means a probability of 5/9.

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document.write( "To have a 'successful' 4-digit number, the 1st digit must be 1 or 2 and the 4th\r\n" );
document.write( "digit must be 1,3,5,7 or 9.\r\n" );
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document.write( "Since the first and last digits can't both be 1, we must break the problem\r\n" );
document.write( "down into two cases:\r\n" );
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document.write( "Case 1: The 1st digit is 1 and the last digit is 3,5,7 or 9. \r\n" );
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document.write( "That's 4 ways the 1st and 4th digits can be to have a successful number.\r\n" );
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document.write( "Case 2: The 1st digit is 2 and the last digit is 1,3,5,7,or 9. \r\n" );
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document.write( "That's 5 ways the 1st and 4th digits can be to have a successful number.\r\n" );
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document.write( "That's 4+5 or 9 ways the 1st and 4th digits can be to have a successful 4-digit\r\n" );
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document.write( "There are 9∙8 or 72 ways the 1st and 4th digits can be to have either a\r\n" );
document.write( "successful or an unsuccessful number.\r\n" );
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document.write( "That's 9 ways out of 72 or 9/72 which reduces to 1/8.\r\n" );
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document.write( "Edwin

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