document.write( "Question 1153828: A box obtains 9 balls marked 1 to 9. Four ball are drawn in succession without replacement. Determine the probability that the four-digit number formed is:\r
\n" );
document.write( "\n" );
document.write( "A. Even\r
\n" );
document.write( "\n" );
document.write( "B. Greater than 5000\r
\n" );
document.write( "\n" );
document.write( "C. An odd number less than 3000 \n" );
document.write( "
Algebra.Com's Answer #776129 by greenestamps(13203)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "A. P(even) \n" ); document.write( "The last ball drawn has to be even. 4 of the 9 balls are even. \n" ); document.write( "P(even) = 4/9 \n" ); document.write( "B. P(greater than 5000) \n" ); document.write( "The first ball drawn has to be 5 or greater. 5 of the 9 balls are 5 or greater. \n" ); document.write( "P(greater than 5000) = 5/9 \n" ); document.write( "C. P(odd and less than 3000) \n" ); document.write( "We have to separate this into two cases. The last ball drawn has to be odd; the first has to be either 1 or 2. \n" ); document.write( "If the first ball drawn is the 1 (probability 1/9), then 4 of the remaining 8 balls are odd. \n" ); document.write( "P(odd number with first digit 1) = (1/9)(4/8) = 4/72 \n" ); document.write( "If the first ball drawn is the 2 (also probability 1/9), then 5 of the remaining 8 balls are odd. \n" ); document.write( "P(odd number with first digit 2) = (1/9)(5/8) = 5/72 \n" ); document.write( "P(odd number less than 3000) = 4/72+5/72 = 9/72 = 1/8 \n" ); document.write( " \n" ); document.write( " |