document.write( "Question 1153816: In parallelogram ABCD, m∠ABD = 83°, m∠BDA = 34°, and m∠BCD =
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Algebra.Com's Answer #776119 by ikleyn(53765) You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Tutor @MathLover1 is trying to solve the problem, even without reading it, so, she is WRONG.\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "In triangle ABD, you are given two angles, ABD and BDA.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Their sum is 83° + 34° = 117°.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Angle A (same as angle DAB) is, therefore, the supplementary angle to 117°,\r\n" ); document.write( "\r\n" ); document.write( "so the measure of the angle DAB is 180° - 117° = 63°.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Angle BCD is the opposite angle in parallelogram ABCD to the angle DAB, so its measure is 63°. ANSWER\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |