document.write( "Question 1153816: In parallelogram ABCD, m∠ABD = 83°, m∠BDA = 34°, and m∠BCD =
\n" ); document.write( "°.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #776119 by ikleyn(53765)\"\" \"About 
You can put this solution on YOUR website!
.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "            Tutor @MathLover1 is trying to solve the problem,  even without reading it,  so,  she is  WRONG.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "In triangle ABD, you are given two angles, ABD and BDA.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Their sum is 83° + 34° = 117°.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Angle A (same as angle DAB) is, therefore, the supplementary angle to 117°,\r\n" );
document.write( "\r\n" );
document.write( "so the measure of the angle DAB is 180° - 117° = 63°.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Angle  BCD is the opposite angle in parallelogram ABCD to the angle DAB, so its measure is 63°.    ANSWER\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );