document.write( "Question 1153785: a rectangle has an area of 84 square feet. the width is x and the length is x+5. find the dimension of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #776065 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "Method 1:
\n" ); document.write( "Look for factors of 84 that have a difference of 5:\r
\n" ); document.write( "\n" ); document.write( "84 =
\n" ); document.write( "4*21
\n" ); document.write( "6*14
\n" ); document.write( "7*12 <--- width is 7, length is 12\r
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\n" ); document.write( "\n" ); document.write( "Method 2:
\n" ); document.write( "Solve algebraically.
\n" ); document.write( "\"+x%2A%28x%2B5%29+=+84+\"
\n" ); document.write( "\"+x%5E2+%2B+5x+-+84+=+0+\"
\n" ); document.write( "// Note that method 1 is basically the same as factoring this expression\r
\n" ); document.write( "\n" ); document.write( "\"+%28x-7%29%2A%28x%2B12%29+=+0+\" --> x = 7 (width) and x + 5 = 12 (length)\r
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