document.write( "Question 1153725: Find all values of x satisfying the given condition.
\n" ); document.write( "y1 = 5x+ 3, y2 = x+ 7, y3 = x, and the difference between 3 times y1 and 14 times y2 is 89 less than y3.
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Algebra.Com's Answer #776017 by ikleyn(52794) $\"\"$ $\"About$

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document.write( "First, you write this basic equation from the condition\r\n" );
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document.write( "    3*y1 - 14*y2 = y3 - 89.           (1)\r\n" );
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document.write( "Then you substitute given expressions for y1, y2 and y3 into this equation.  You get\r\n" );
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document.write( "    3*(5x+3) - 14*(x+7) = x - 89.     (2)\r\n" );
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document.write( "Next, you simplify the equation step by step\r\n" );
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document.write( "    15x + 9 - 14x - 98 = x - 89\r\n" );
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document.write( "    (15x - 14x) + (9 - 98) = x - 89\r\n" );
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document.write( "     x          + (-89)    = x - 89\r\n" );
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document.write( "     x - x                 = 89 - 89\r\n" );
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document.write( "     0                     = 0.\r\n" );
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document.write( "You get a true identity.  It means that equations (1) and/or (2) has INFINITELY MANY solutions.\r\n" );
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document.write( "Any value of x provides a valid solution.\r\n" );
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document.write( "The ANSWER is option B.\r\n" );
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