document.write( "Question 1153715: Julia and her children went into a movie theater and where they sell drinks for $5.50 each and pretzels for $4 each. Julia has $90 to spend and must buy at least 18 drinks and pretzels altogether. If Julia decided to buy 5 drinks, determine the maximum number of pretzels that she could buy. If there are no possible solutions, submit an empty answer. \n" ); document.write( "
Algebra.Com's Answer #775999 by josmiceli(19441)\"\" \"About 
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Let \"+a+\" = number of drinks she buys
\n" ); document.write( "Let \"+b+\" = number of pretzels she buys
\n" ); document.write( "------------------------------------------------
\n" ); document.write( "\"+5.5a+%2B+4b+%3C=+90+\"
\n" ); document.write( "\"+a+%2B+b+%3E=+18+\"
\n" ); document.write( "\"+a+=+5+\"
\n" ); document.write( "\"+5+%2B+b+%3E=+18+\"
\n" ); document.write( "\"+b+%3E=+13+\"
\n" ); document.write( "-------------------
\n" ); document.write( "\"+5.5%2A5+%2B+4b+%3C=+90+\"
\n" ); document.write( "\"+27.5+%2B+4b+%3C=+90+\"
\n" ); document.write( "\"+4b+%3C=+62.5+\"
\n" ); document.write( "\"+b+%3C=+15.625+\"
\n" ); document.write( "you can't have part of a pretzel, so
\n" ); document.write( "the maximum number of pretzels
\n" ); document.write( "is 15
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\n" ); document.write( "get a 2nd opinion if needed\r
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