document.write( "Question 1153710: originally a rectangle was three times as long as it was wide. when 2 cm were subtracted from the length and 5 cm were added to the width, the resulting rectangle had an are of 90cm^2. what the dimensions of the new rectangle
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Algebra.Com's Answer #775987 by josgarithmetic(39617)\"\" \"About 
You can put this solution on YOUR website!
This method may seem slightly backward, but:
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\n" ); document.write( "3x, the original length\r
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\n" ); document.write( "\n" ); document.write( "\"%283x-2%29%28x%2B5%29=90\"
\n" ); document.write( "Solve any way you wish. Question asks for each of the two factors.\r
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\n" ); document.write( "\n" ); document.write( "\"3%2A4-2=highlight%2810%29\"-----length of the new rectangle
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\n" ); document.write( "\"4%2B5=highlight%289%29\"------width of new rectangle
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