document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153698>Question 1153698</A>: <I><SPAN STYLE=\"word-break: break-all;\"> From a place 400 m north of X, a student walks eastwards to a place Y which 800m from X. What is the bearing of X from Y?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775969 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775969\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Draw this.  It is a 1-sqrt(3)- 2 30-60-90 right triangle<BR>\n" );
document.write( "Angle Y is 30 degrees and it is 30 degrees south of due west, so the bearing is 240 degrees. </SPAN>\n" );
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