document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153682>Question 1153682</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Can you help me solve this problem/<BR>\n" );
document.write( "How much of a 60% orange juice drink must be mixed with 14 gallons of a 20% orange juice drink to obtain a mixture that is 50% orange juice\r<BR>\n" );
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document.write( "The amount of 60% orange juice drink is ____ gallons </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775956 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775956\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If a formal algebraic solution is not required, here is a method that will get you to the answer to this and many similar problems with very little effort.<br><BR>\n" );
document.write( "Think of the problem as starting with 20% juice and adding 60% juice, stopping when the mixture is 50% juice.<br><BR>\n" );
document.write( "50% is 3/4 of the way from 20% to 60%.  (20 to 60 is 40; 20 to 50 is 30; 30/40 = 3/4.)<br><BR>\n" );
document.write( "That means 3/4 of the mixture must be the 60% juice you are adding.<br><BR>\n" );
document.write( "So the original 14 gallons of 20% juice is 1/4 of the mixture; that means the 3/4 of the mixture that is the added 60% juice is 3*14 = 42 gallons.<br><BR>\n" );
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