document.write( "Question 1153657: A total of $7000 is invested: part at 6% and the remainder at 10%. How much is invested at each rate if the annual interest is $470? \n" ); document.write( "
Algebra.Com's Answer #775929 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "A total of $\"7000\" is invested: \r
\n" ); document.write( "\n" ); document.write( "part \"x\" at \"6\"% and the remainder \"7000-x\" at \"10\"%. How much is invested at each rate if the annual interest is $\"470\"?\r
\n" ); document.write( "\n" ); document.write( "\"0.06x%2B0.10%287000-x%29=470\"\r
\n" ); document.write( "\n" ); document.write( "\"0.06x%2B700-0.10x=470\"\r
\n" ); document.write( "\n" ); document.write( "\"0.06x-0.10x=470-700\"\r
\n" ); document.write( "\n" ); document.write( "\"-0.04x=-230\"\r
\n" ); document.write( "\n" ); document.write( "\"x=-230%2F-0.04\"\r
\n" ); document.write( "\n" ); document.write( "\"x=5750\"->invested at each \"6\"% rate\r
\n" ); document.write( "\n" ); document.write( "then, other part is: \r
\n" ); document.write( "\n" ); document.write( "\"7000-x=7000-5750=1250\"->invested at each \"10\"% rate\r
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\n" ); document.write( "\n" ); document.write( "check:\r
\n" ); document.write( "\n" ); document.write( "\"0.06%2A5750%2B0.10%2A1250=345%2B125=470\"\r
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