document.write( "Question 15696: Please can you help with this question:\r
\n" ); document.write( "\n" ); document.write( "Given that, for all values of x: \"f%28x%29=3x%5E2%2B12x%2B5=p%28x%2Bq%29%5E2%2Br\"\r
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Algebra.Com's Answer #7759 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
Given that, for all values of x: \"f%28x%29=3x%5E2%2B12x%2B5=p%28x%2Bq%29%5E2%2Br\"\r
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\n" ); document.write( " the given equation is a second degree polynomial in x and should have 2 roots or it should be satisfied by 2 values of x . but it is given that it is true for all values of x . so it is an identity . so coefficients of corresponding terms on either side of the identity shall be equal
\n" ); document.write( " l.h.s.=\"f%28x%29=3x%5E2%2B12x%2B5\"=r.h.s.=\"p%28x%2Bq%29%5E2%2Br\"=\"px%5E2%2B2%2Ap%2Aq%2Ax%2Bp%2Aq%5E2%2Br\"
\n" ); document.write( "hence 3=p
\n" ); document.write( " 12 = 2p*q or...... q=12/2*p = 12/2*3 = 12/6 =2
\n" ); document.write( " 5= \"p%2Aq%5E2%2Br\"= 3*2^2+r=12+r...or.....r=5-12 = -7
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