document.write( "Question 1153632: Find the value of x for which the tangent line to \"y=2x%5E2+%2B+1\" will be parallel to the tangent line to \"y+=+4ln%28x%29+-+3\"? \n" ); document.write( "
Algebra.Com's Answer #775894 by Alan3354(69443)\"\" \"About 
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Find the value of x for which the tangent line to \"y=2x%5E2+%2B+1\" will be parallel to the tangent line to \"y+=+4ln%28x%29+-+3\"?
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\n" ); document.write( "Slope of \"y=2x%5E2+%2B+1\" = 4x.
\n" ); document.write( "Slope of \"y+=+4ln%28x%29+-+3\" = 4/x
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\n" ); document.write( "4x = 4/x
\n" ); document.write( "x = 1
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\n" ); document.write( "The 2 slopes are 4 so they're parallel.
\n" ); document.write( "There are an infinite # of other slopes tangent to the 2 curves that are parallel.
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\n" ); document.write( "Mathlover switched to \"y+=+4ln%28x%29+%2B+3\"
\n" ); document.write( "Maybe that's what you meant?
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\n" ); document.write( "I'm not blind, but I do use reading glasses.
\n" ); document.write( "IDK how I was supposed to spot the alleged plagiarism, but I'm not overly worried about that.
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\n" ); document.write( "What I find interesting is that only x = 1 is a solution algebraically, but there are an infinite # of other lines that are parallel to the 2 graphs.
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