document.write( "Question 106610: How would you solve this by using the elimination method? \r
\n" ); document.write( "\n" ); document.write( "2x+12y=7
\n" ); document.write( "3x+4y=1
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Algebra.Com's Answer #77589 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
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Solved by pluggable solver: Solving a System of Linear Equations by Elimination/Addition

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\n" ); document.write( " Lets start with the given system of linear equations
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\n" ); document.write( " \"2%2Ax%2B12%2Ay=7\"
\n" ); document.write( " \"3%2Ax%2B4%2Ay=1\"
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\n" ); document.write( " In order to solve for one variable, we must eliminate the other variable. So if we wanted to solve for y, we would have to eliminate x (or vice versa).
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\n" ); document.write( " So lets eliminate x. In order to do that, we need to have both x coefficients that are equal but have opposite signs (for instance 2 and -2 are equal but have opposite signs). This way they will add to zero.
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\n" ); document.write( " So to make the x coefficients equal but opposite, we need to multiply both x coefficients by some number to get them to an equal number. So if we wanted to get 2 and 3 to some equal number, we could try to get them to the LCM.
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\n" ); document.write( " Since the LCM of 2 and 3 is 6, we need to multiply both sides of the top equation by 3 and multiply both sides of the bottom equation by -2 like this:
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\n" ); document.write( " \"3%2A%282%2Ax%2B12%2Ay%29=%287%29%2A3\" Multiply the top equation (both sides) by 3
\n" ); document.write( " \"-2%2A%283%2Ax%2B4%2Ay%29=%281%29%2A-2\" Multiply the bottom equation (both sides) by -2
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\n" ); document.write( " So after multiplying we get this:
\n" ); document.write( " \"6%2Ax%2B36%2Ay=21\"
\n" ); document.write( " \"-6%2Ax-8%2Ay=-2\"
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\n" ); document.write( " Notice how 6 and -6 add to zero (ie \"6%2B-6=0\")
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\n" ); document.write( " Now add the equations together. In order to add 2 equations, group like terms and combine them
\n" ); document.write( " \"%286%2Ax-6%2Ax%29%2B%2836%2Ay-8%2Ay%29=21-2\"
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\n" ); document.write( " \"%286-6%29%2Ax%2B%2836-8%29y=21-2\"
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\n" ); document.write( " \"cross%286%2B-6%29%2Ax%2B%2836-8%29%2Ay=21-2\" Notice the x coefficients add to zero and cancel out. This means we've eliminated x altogether.
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\n" ); document.write( " So after adding and canceling out the x terms we're left with:
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\n" ); document.write( " \"28%2Ay=19\"
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\n" ); document.write( " \"y=19%2F28\" Divide both sides by \"28\" to solve for y
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\n" ); document.write( " \"y=19%2F28\" Reduce
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\n" ); document.write( " Now plug this answer into the top equation \"2%2Ax%2B12%2Ay=7\" to solve for x
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\n" ); document.write( " \"2%2Ax%2B12%2819%2F28%29=7\" Plug in \"y=19%2F28\"
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\n" ); document.write( " \"2%2Ax%2B228%2F28=7\" Multiply
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\n" ); document.write( " \"2%2Ax%2B57%2F7=7\" Reduce
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\n" ); document.write( " \"2%2Ax=7-57%2F7\" Subtract \"57%2F7\" from both sides
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\n" ); document.write( " \"2%2Ax=49%2F7-57%2F7\" Make 7 into a fraction with a denominator of 7
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\n" ); document.write( " \"2%2Ax=-8%2F7\" Combine the terms on the right side
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\n" ); document.write( " \"cross%28%281%2F2%29%282%29%29%2Ax=%28-8%2F7%29%281%2F2%29\" Multiply both sides by \"1%2F2\". This will cancel out \"2\" on the left side.
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\n" ); document.write( " \"x=-4%2F7\" Multiply the terms on the right side
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\n" ); document.write( " So our answer is
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\n" ); document.write( " \"x=-4%2F7\", \"y=19%2F28\"
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\n" ); document.write( " which also looks like
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\n" ); document.write( " (\"-4%2F7\", \"19%2F28\")
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\n" ); document.write( " Notice if we graph the equations (if you need help with graphing, check out this solver)
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\n" ); document.write( " \"2%2Ax%2B12%2Ay=7\"
\n" ); document.write( " \"3%2Ax%2B4%2Ay=1\"
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\n" ); document.write( " we get
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\n" ); document.write( " graph of \"2%2Ax%2B12%2Ay=7\" (red) \"3%2Ax%2B4%2Ay=1\" (green) (hint: you may have to solve for y to graph these) and the intersection of the lines (blue circle).
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\n" ); document.write( " and we can see that the two equations intersect at (\"-4%2F7\",\"19%2F28\"). This verifies our answer.
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