document.write( "Question 1153592: Four times the ones digit of a positive, two digit integer is 25 greater than the sum of the digits. Reversing the digits increases the number by 63. What is the number? \n" ); document.write( "
Algebra.Com's Answer #775859 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Here is a quick path to the answer, if a formal algebraic solution is not required.

\n" ); document.write( "The difference between a 2-digit number and the 2-digit number with the digits reversed is 9 times the difference of the two digits.

\n" ); document.write( "The given number is increased by 63 = 9*7 when the digits are reversed, so the difference between the digits is 7. That means the 2-digit number can be only 18 or 29.

\n" ); document.write( "18 doesn't satisfy the condition that the ones digit is 25 more than the sum of the digits; 29 does.

\n" ); document.write( "ANSWER: 29

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