document.write( "Question 1153575: I can’t find the x- and y-intercepts of this equation: \"4y+%2B+5x+=+2y+-+3x+%2B+16\". I have already tried finding the X intercept by replacing all of the Y coefficients in the equation with 4(0) and 2(0) and, after simplifying everything, I got: -5x= -3x+16. So I did what I thought I should have done, which was dividing -5X by -5 to isolate the variable, and did the same on the other side. But, I am not sure as to where to put the other (divided by -5). So I tried both: \"%28-5x%29%2F-5=%28-3x%2B16%29%2F-5\" and \"%28-5x%29%2F-5=%28-3x%29%2F-5%2B16%2F-5\". The first one resulted in x=0.6x and the second one became x=0.6x-3.2, I think. I don’t know what to do with this, please help. \n" ); document.write( "
Algebra.Com's Answer #775830 by Alan3354(69443)\"\" \"About 
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I can’t find the x- and y-intercepts of this equation:
\n" ); document.write( "\"4y+%2B+5x+=+2y+-+3x+%2B+16\"
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\n" ); document.write( "I would simplify first:
\n" ); document.write( "2y + 8x = 16
\n" ); document.write( "4x + y = 8
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\n" ); document.write( "For the y-int, x = 0
\n" ); document.write( "y = 8, or the point (0,8)
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\n" ); document.write( "For the x-int, y = 0
\n" ); document.write( "4x = 8
\n" ); document.write( "x = 2, or the point (2,0)\r
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