document.write( "Question 1153556: Several friends decided to equally share the $525 cost of the set of cookware for a wedding gift. However, before the wedding, 6 more friends joined the others in giving the couple the cookwares. This lowered the contribution of each person by $10. How many friends originally agreed to share of the cost of the cookware? \n" ); document.write( "
Algebra.Com's Answer #775811 by VFBundy(438)\"\" \"About 
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Original number of friends = x
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\n" ); document.write( "\"525%2Fx\" = \"%28525%2F%28x%2B6%29%29+%2B+10\"
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\n" ); document.write( "\"525%2Fx\" = \"%28525%2F%28x%2B6%29%29+%2B+%2810%28x%2B6%29%2F%28x%2B6%29%29\"
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\n" ); document.write( "\"525%2Fx\" = \"%28525%2F%28x%2B6%29%29+%2B+%28%2810x%2B60%29%2F%28x%2B6%29%29\"
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\n" ); document.write( "\"525%2Fx\" = \"%2810x%2B585%29%2F%28x%2B6%29\"
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\n" ); document.write( "525(x+6) = x(10x+585)
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\n" ); document.write( "525x + 3150 = 10x² + 585x
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\n" ); document.write( "10x² + 60x - 3150 = 0
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\n" ); document.write( "x² + 6x - 315 = 0
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\n" ); document.write( "(x - 15)(x + 21) = 0
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\n" ); document.write( "x = 15 and x = -21. Since x (the original number of friends) cannot be a negative number, this leaves us with x = 15.
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\n" ); document.write( "Original number of friends = x = 15
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