document.write( "Question 1153494: Three times Jack’s age +2 times Jill’s age equals 64. Jack is also two times Jill’s age. how old is Jack? \n" ); document.write( "
Algebra.Com's Answer #775714 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "let Jack’s age be \"x\", \r
\n" ); document.write( "\n" ); document.write( " Jill’s age \"y\"\r
\n" ); document.write( "\n" ); document.write( "if three times Jack’s age +\"2\" times Jill’s age equals \"64\", we have\r
\n" ); document.write( "\n" ); document.write( "\"3x%2B2y=64\"......eq.1\r
\n" ); document.write( "\n" ); document.write( "if Jack is also two times Jill’s age, then Jack is: \r
\n" ); document.write( "\n" ); document.write( "\"x=2y\".....eq.2\r
\n" ); document.write( "\n" ); document.write( "go to \r
\n" ); document.write( "\n" ); document.write( "\"3x%2B2y=64\"......eq.1, substitute \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"3%2A2y%2B2y=64\"......solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"6y%2B2y=64\"\r
\n" ); document.write( "\n" ); document.write( "\"8y=64\"\r
\n" ); document.write( "\n" ); document.write( "\"y=64%2F8\"\r
\n" ); document.write( "\n" ); document.write( "\"y=+8\"\r
\n" ); document.write( "\n" ); document.write( "go to eq.2\r
\n" ); document.write( "\n" ); document.write( "\"x=2y\".....eq.2, substitute \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"x=2%2A8\"\r
\n" ); document.write( "\n" ); document.write( "\"x=16\"\r
\n" ); document.write( "\n" ); document.write( "so, Jack is \"16\" years old\r
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