document.write( "Question 1153427: What are the x and y intercepts of these equations
\n" ); document.write( "1. f(x)={√x^2, -3≤ x< 0 {x^2 , 0≤ x ≥ 2
\n" ); document.write( "2. f(x)={2x, -3≤ x< 0 {1, 0≤ x ≥ 4
\n" ); document.write( "3. f(x)={x, 0≤ x< 5 {x-1, -2≤ x ≥ 2
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Algebra.Com's Answer #775711 by greenestamps(13215)\"\" \"About 
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\n" ); document.write( "Note that none of the descriptions of the functions is valid; specifying a range of values as \"0≤ x ≥ 2\" is meaningless. I will assume that in each example the intended range is like \"0≤ x ≤ 2\"
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document.write( "1. \"y+=+sqrt%28x%5E2%29\" on [-3,0);\r\n" );
document.write( "   \"y+=+x%5E2\" on [0,2]

\n" ); document.write( "For negative values of x, \"sqrt%28x%5E2%29+=+-x\". On the interval [-3,0), neither x nor -x has the value 0; there are no x- or y-intercepts on that part of the
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\n" ); document.write( "For non-negative values of x, on the interval [0,2] both the x and y values are 0 only at x=0. The x- and y-intercepts are both (0,0).

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document.write( "2. \"y+=+2x\" on [-3,0);\r\n" );
document.write( "   \"y+=+1\" on [0,4]

\n" ); document.write( "On the interval [-3,0), x is always negative, so y=2x is always negative; there are no x- or y-intercepts on that part of the graph.

\n" ); document.write( "On the interval [0,4], x is clearly 0 at x=0; y is always 1, so it is never 0. This function has an x-intercept at (0,1) and no y-intercept.

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document.write( "3. \"y+=+x\" on [0,5);\r\n" );
document.write( "   \"y+=+x-1\" on [-2,2]

\n" ); document.write( "This definition is not valid; the definition results in two different values on the interval [0,2].

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