document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153483>Question 1153483</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use an Algebraic equation to determine each rectangle's dimensions.\r<BR>\n" );
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document.write( "An American football field is a rectangle with a perimeter of 1040 feet. The length is 200 feet more than the width. Find the width and length of the rectangular field.<BR>\n" );
document.write( "Thank you in advance,<BR>\n" );
document.write( "SYL </SPAN>\n" );
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document.write( "w = width; w+200 = length<br><BR>\n" );
document.write( "perimeter = 2(length+width)<br><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2%28w%2B%28w%2B200%29%29+=+1040 ALIGN=MIDDLE  ALT=\"2%28w%2B%28w%2B200%29%29+=+1040\"   DISABLED_style= \"max-width:90%; height:auto;\" ><br><BR>\n" );
document.write( "Solve using basic algebra....<br><BR>\n" );
document.write( "Without algebra....<br><BR>\n" );
document.write( "Imagine shortening the field by 200 feet, so that the length and width are the same.  That makes the perimeter 1040-400 = 640 feet.<br><BR>\n" );
document.write( "With length and width the same, the field is square; each side is one-quarter of the perimeter: 640/4 = 160.<br><BR>\n" );
document.write( "So the width of the field is 160 feet.<br><BR>\n" );
document.write( "Now add the 200 feet back on to the length to get 360 feet for the length.<br><BR>\n" );
document.write( "ANSWER: width 160 feet; length 360 feet<br> </SPAN>\n" );
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