document.write( "Question 106565: solve by factoring
\n" ); document.write( "x cubed-9x=0\r
\n" ); document.write( "\n" ); document.write( "y squared-2y-24=0
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Algebra.Com's Answer #77570 by ashlyn.xo(7)\"\" \"About 
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\"x%5E3-9x=0\"
\n" ); document.write( "this equation cannot be factored, because there is no square root of \"x%5E3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y%5E2-2y-24=0\"
\n" ); document.write( "GAME: think of 2 numbers that is the product to the 3rd term (-24) and the sum of the 2nd term (-2).
\n" ); document.write( "These two numbers would be: -6,4
\n" ); document.write( "This is because: \"-6%2A4=-24\"
\n" ); document.write( "And: \"-6%2B4=-2\"\r
\n" ); document.write( "\n" ); document.write( "now, substitute these two numbers as the middle term in the equation:
\n" ); document.write( "\"y%5E2-6y%2B4y-24=0\"\r
\n" ); document.write( "\n" ); document.write( "Now, common factor by GROUPING
\n" ); document.write( "-Common Factor the first two terms
\n" ); document.write( "-Common factor of \"y%5E2-6y\" is y
\n" ); document.write( "-Common Factor the last two terms
\n" ); document.write( "-Common factor of \"4y-24\" is 4\r
\n" ); document.write( "\n" ); document.write( "Therefore, the equation is now \"y%28y-6%29%2B4%28y-6%29=0\" after dividing by the common factors.\r
\n" ); document.write( "\n" ); document.write( "Take the equation \"y%28y-6%29%2B4%28y-6%29=0\" and common factor again, this time the common factor being (y-6)\r
\n" ); document.write( "\n" ); document.write( "Therefore, \"%28y-6%29%2A%28y-4%29=0\"\r
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