document.write( "Question 15694: Please can you resolve this into partial fractions\r
\n" ); document.write( "\n" ); document.write( "\"x+%2F+%28x-1%29%28x%5E2+-+4%29\"
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Algebra.Com's Answer #7757 by venugopalramana(3286)\"\" \"About 
You can put this solution on YOUR website!
\"x+%2F+%28x-1%29%28x%5E2+-+4%29\" = \"x%2F%28%28x-1%29%28x%2B2%29%28x-2%29%29\"
\n" ); document.write( " Let this be equal to \"a%2F%28x-1%29%2Bb%2F%28x%2B2%29%2Bc%2F%28x-2%29\"
\n" ); document.write( " = =
\n" ); document.write( " \"x%2F%28%28x-1%29%28x%2B2%29%28x-2%29%29\"
\n" ); document.write( " Since denominators are same , equating the numerators we get
\n" ); document.write( " \"a%28x%2B2%29%28x-2%29%2Bb%28x-1%29%28x-2%29%2Bc%28x-1%29%28x%2B2%29\"=x
\n" ); document.write( " since this is an identity , it is true for any value of x
\n" ); document.write( " hence take x=1,and -2 and 2 to get a ,b , c values
\n" ); document.write( " for x=1 ,we have
\n" ); document.write( " a(1+2)(1-2)=1
\n" ); document.write( "a = -1/3 similarly we get b=-2/12=-1/6 and c=2/4 = 1/2
\n" ); document.write( " hence
\n" ); document.write( "\"x+%2F+%28x-1%29%28x%5E2+-+4%29\"=
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