document.write( "Question 1153467: Find an equation of a rational function that satisfies the following conditions:
\n" ); document.write( "• Vertical asymptotes: x = −3
\n" ); document.write( "• Horizontal asymptote: y=3/2
\n" ); document.write( "• x -intercept: 5
\n" ); document.write( "• Hole at x =2
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Algebra.Com's Answer #775689 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "vertical asymptote at x = -3:
\n" ); document.write( "This requires a factor of (x+3) in the denominator, without a like factor in the numerator:
\n" ); document.write( "\"1%2F%28x%2B3%29\"

\n" ); document.write( "horizontal asymptote at y = 3/2:
\n" ); document.write( "(We will take care of this last)

\n" ); document.write( "x-intercept at x=5:
\n" ); document.write( "This requires a factor of (x-5) in the numerator, without a like factor in the denominator:
\n" ); document.write( "\"%28x-5%29%2F%28x%2B3%29\"

\n" ); document.write( "Hole at x=2:
\n" ); document.write( "This requires factors of (x-2) in BOTH numerator and denominator:
\n" ); document.write( "\"%28%28x-5%29%28x-2%29%29%2F%28%28x%2B3%29%28x-2%29%29\"

\n" ); document.write( "horizontal asymptote at y = 3/2:
\n" ); document.write( "This requires the numerator and denominator to be the same degree, with the ratio of leading coefficients 3:2. The degrees of the numerator and denominator are the same at this point; we just need to add constant factors to make the ratio of the leading coefficients equal to 3/2.
\n" ); document.write( "\"%283%28x-5%29%28x-2%29%29%2F%282%28x%2B3%29%28x-2%29%29\"

\n" ); document.write( "A graph showing the vertical asymptote at x = -3 and the x-intercept at x=5:

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\n" ); document.write( "A graph showing the horizontal asymptote at y = 3/2:

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\n" ); document.write( "The graphing utility used on this site won't show the hole in the graph at x=2. A good graphing calculator like the TI-83 will show it if you graph the function on a very small range of values of x either side of x=2.
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