document.write( "Question 1153438: x −2 −1 0 1 2
\n" ); document.write( "y 9 4 1 0 1
\n" ); document.write( "Use the table of values that represent points on the graph of a quadratic function. By determining the vertex and axis of symmetry, find the general form of the equation of the quadratic function.
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Algebra.Com's Answer #775654 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\"x\"| \"-2\",\"+-1\", \"0\", \"1\",\"+2\"
\n" ); document.write( "\"y\"|\"+9\", \"4\", \"1\",\"+0\", \"1\"\r
\n" ); document.write( "\n" ); document.write( "\"y=ax%5E2%2Bbx%2Bc\"..........use given \"x\" and \"y\" values to calculate coefficients \"a\", \"b\", and constant \"c\"\r
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\n" ); document.write( "\n" ); document.write( "\"9=a%28-2%29%5E2%2Bb%28-2%29%2Bc\"
\n" ); document.write( "\"9=4a-2b%2Bc\"............eq.1\r
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\n" ); document.write( "\n" ); document.write( "\"4=a%28-1%29%5E2%2Bb%28-1%29%2Bc\"
\n" ); document.write( "\"4=a-b%2Bc\"............eq.2\r
\n" ); document.write( "\n" ); document.write( "\"1=a%280%29%5E2%2Bb%280%29%2Bc\"
\n" ); document.write( "\"1=c\"............eq.3\r
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\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"9=4a-2b%2Bc\"............eq.1, plug in \"c\"
\n" ); document.write( "\"9=4a-2b%2B1\"............solve for \"b\"
\n" ); document.write( "\"2b=4a-9%2B1\"
\n" ); document.write( "\"2b=4a-8\"
\n" ); document.write( "\"b=2a-4\"..........1a\r
\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"4=a-b%2Bc\"............eq.2, plug in \"c\"
\n" ); document.write( "\"4=a-b%2B1\"...........solve for \"b\"
\n" ); document.write( "\"b=a-4%2B1\"
\n" ); document.write( "\"b=a-3\"..........2a\r
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\n" ); document.write( "\n" ); document.write( "from 1a and 2a we have\r
\n" ); document.write( "\n" ); document.write( "\"2a-4=a-3\".......solve for\"+a\"
\n" ); document.write( "\"2a-a=4-3\"
\n" ); document.write( "\"a=1\"\r
\n" ); document.write( "\n" ); document.write( "go to\r
\n" ); document.write( "\n" ); document.write( "\"b=a-3\"..........2a,plug in \"a\"
\n" ); document.write( "\"b=1-3\"
\n" ); document.write( "\"b=-2\"\r
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\n" ); document.write( "\n" ); document.write( "your equation is:\r
\n" ); document.write( "\n" ); document.write( "\"y=x%5E2-2x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "determining the vertex: write it in vertex form\r
\n" ); document.write( "\n" ); document.write( "\"y=%28x-1%29%5E2%2B0\"=> the vertex is at (\"1\",\"0\")\r
\n" ); document.write( "\n" ); document.write( "and axis of symmetry is \"x=1\"\r
\n" ); document.write( "\n" ); document.write( "the general form of the equation of the quadratic function:\r
\n" ); document.write( "\n" ); document.write( "\"ax%5E2+%2B+bx+%2B+c+=+0\"=> in your case \"x%5E2+-2x+%2B+1=+0\"\r
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