document.write( "Question 1153401:
\n" ); document.write( "The floor of a shed given on the right has an area of 75 square feet. The floor is in the shape of a rectangle whose length is 5 feet less than twice the width. Find the length and the width of the floor of the shed.
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #775614 by ikleyn(52781)\"\" \"About 
You can put this solution on YOUR website!
.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "            MENTAL   SOLUTION\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\r\n" );
document.write( "Let the width be w feet; then the length is  (2w-5) feet.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "The equation for the area is\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    w*(2w-5) = 75.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Double both sides\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "    2w*(2w-5) = 150.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "Two numbers that give the product 150 and differ in 5 units are 10 and 15.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "So, 2w = 15;  hence, w = 7.5.\r\n" );
document.write( "\r\n" );
document.write( "\r\n" );
document.write( "ANSWER.  The width is 7.5 ft;  the length is 2*7.5-5 = 10 ft.\r\n" );
document.write( "
\r
\n" ); document.write( "\n" ); document.write( "Solved.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );