document.write( "Question 1153401:
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document.write( "The floor of a shed given on the right has an area of 75 square feet. The floor is in the shape of a rectangle whose length is 5 feet less than twice the width. Find the length and the width of the floor of the shed.
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Algebra.Com's Answer #775614 by ikleyn(52781)![]() ![]() You can put this solution on YOUR website! .\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " MENTAL SOLUTION\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \r\n" ); document.write( "Let the width be w feet; then the length is (2w-5) feet.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "The equation for the area is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " w*(2w-5) = 75.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Double both sides\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 2w*(2w-5) = 150.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Two numbers that give the product 150 and differ in 5 units are 10 and 15.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "So, 2w = 15; hence, w = 7.5.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "ANSWER. The width is 7.5 ft; the length is 2*7.5-5 = 10 ft.\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |