document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153373>Question 1153373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Jordan is 12 years older than Anna the sum of their ages is 50 find the age of each person  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775601 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775601\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Note if a formal algebraic solution is not required, there is a common strategy that can make problems like this easy to solve mentally.<br><BR>\n" );
document.write( "Think of rewording the problem to say the ages differ by 12 years and their sum is 50.  Then reason as follows:<br><BR>\n" );
document.write( "(1) Two ages that are the same and have a sum of 50 are 25 and 25.<BR>\n" );
document.write( "(2) To get two ages that differ by 12, take the two 25s and add 6 to one and subtract 6 from the other.<br><BR>\n" );
document.write( "That gives you the answer: the ages are 25+6=31 and 25-6=19.<br><BR>\n" );
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