document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153276>Question 1153276</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In a random sample of six mobile​ devices, the mean repair cost was ​$60.00 and the standard deviation was ​$11.00. Assume the population is normally distributed and use at-distribution to find the margin of error and construct a 99​% confidence interval for the population mean. Interpret the results.<BR>\n" );
document.write( "The 99​% confidence interval for the population mean mu is ​(  ), (  )<BR>\n" );
document.write( " (Round to two decimal places as​ needed.)\r<BR>\n" );
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document.write( "The margin of error is ( _ )(Round to two decimal places as​needed.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775500 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775500\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> half-interval is tdf=5, 0.005*s/sqrt(n)\r<BR>\n" );
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document.write( "=4.032 (value of t)*11.00*/sqrt(6)<BR>\n" );
document.write( "=$18.11 and this is margin of error<BR>\n" );
document.write( "add and subtract to mean<BR>\n" );
document.write( "($41.89, $78.11)<BR>\n" );
document.write( "We are not exactly sure what the true value is, but we are very highly confident it lies in the above interval. </SPAN>\n" );
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