document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153294>Question 1153294</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a circle is 89.42 cm2. Which of the following most nearly gives the length of the side of a regular hexagon inscribed in the circle?<BR>\n" );
document.write( "A. 4.22 cm <BR>\n" );
document.write( "B. 5.33 cm<BR>\n" );
document.write( "C. 5.89 cm <BR>\n" );
document.write( "D. 6.12 cm </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775490 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20849)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775490\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <a  rel=nofollow HREF=\"https://www.imageupload.net/image/Zx8k1\"><IMG STYLE=\"max-width:80%;\" src=\"https://imagehost.imageupload.net/2020/03/02/Untitled-143-300x199.th.png\" alt=\"Untitled-143-300x199.png\" border=\"0\" /></a>\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "From the figure, it is clear that, we can divide the regular hexagon into 6 identical equilateral triangles.<BR>\n" );
document.write( "We take one triangle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=OAB ALIGN=MIDDLE  ALT=\"OAB\"   DISABLED_style= \"max-width:90%; height:auto;\" >, with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=O+ ALIGN=MIDDLE  ALT=\"O+\"   DISABLED_style= \"max-width:90%; height:auto;\" >as the center of the hexagon or circle, & <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AB+ ALIGN=MIDDLE  ALT=\"AB+\"   DISABLED_style= \"max-width:90%; height:auto;\" >as one side of the hexagon.<BR>\n" );
document.write( "Let <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=M+ ALIGN=MIDDLE  ALT=\"M+\"   DISABLED_style= \"max-width:90%; height:auto;\" >be mid-point of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AB ALIGN=MIDDLE  ALT=\"AB\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=OM ALIGN=MIDDLE  ALT=\"OM\"   DISABLED_style= \"max-width:90%; height:auto;\" > would be the perpendicular bisector of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AB ALIGN=MIDDLE  ALT=\"AB\"   DISABLED_style= \"max-width:90%; height:auto;\" >, angle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AOM+=+30 ALIGN=MIDDLE  ALT=\"AOM+=+30\"   DISABLED_style= \"max-width:90%; height:auto;\" >° \r<BR>\n" );
document.write( "\n" );
document.write( "Then in right angled triangle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=OAM ALIGN=MIDDLE  ALT=\"OAM\"   DISABLED_style= \"max-width:90%; height:auto;\" >, side is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a ALIGN=MIDDLE  ALT=\"a\"   DISABLED_style= \"max-width:90%; height:auto;\" > \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28x%29+=+tan%2830%29+=+1%2Fsqrt%283%29 ALIGN=MIDDLE  ALT=\"tan%28x%29+=+tan%2830%29+=+1%2Fsqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "So, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%2F2r+=+1%2Fsqrt%283%29 ALIGN=MIDDLE  ALT=\"a%2F2r+=+1%2Fsqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Therefore, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+%28a%2Asqrt%283%29%29%2F2 ALIGN=MIDDLE  ALT=\"r+=+%28a%2Asqrt%283%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "Area of circle is, \r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"A+=pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=pi%2A%28%28a%2Asqrt%283%29%29%2F2%29%5E2 ALIGN=MIDDLE  ALT=\"A+=pi%2A%28%28a%2Asqrt%283%29%29%2F2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "if given that the area of a circle is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=89.42cm%5E2 ALIGN=MIDDLE  ALT=\"89.42cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >, we have\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=89.42cm%5E2=%283%2Api%2F4%29a%5E2 ALIGN=MIDDLE  ALT=\"89.42cm%5E2=%283%2Api%2F4%29a%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=89.42cm%5E2+=2.356a%5E2 ALIGN=MIDDLE  ALT=\"89.42cm%5E2+=2.356a%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2=89.42cm%5E2%2F2.356 ALIGN=MIDDLE  ALT=\"a%5E2=89.42cm%5E2%2F2.356\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a%5E2=37.95cm%5E2 ALIGN=MIDDLE  ALT=\"a%5E2=37.95cm%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a=6.16cm ALIGN=MIDDLE  ALT=\"a=6.16cm\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "so, <BR>\n" );
document.write( "D. 6.12 cm -> should be <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=6.16cm ALIGN=MIDDLE  ALT=\"6.16cm\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );