document.write( "Question 1153296: The cross section of a pipe is formed by two concentric circles such that the bigger one circumscribes a regular hexagon of sides measuring 9.40 cm while the other one is inscribed in it. Find the cross-sectional area of the pipe.
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\n" ); document.write( "B.64.90 cm2
\n" ); document.write( "C.60.94 cm2
\n" ); document.write( "D.60.04 cm2
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Algebra.Com's Answer #775489 by ikleyn(52756)\"\" \"About 
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document.write( "The outer radius of the pipe is  R = 9.40 cm.\r\n" );
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document.write( "The interior radius of the pipe is the apothem of the regular hexagon, so its length is  r = \"9.4%2Asqrt%283%29%2F2\" = 8.14 cm.\r\n" );
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document.write( "The cross-sectional are is the difference of the area of the bigger and smaller circles\r\n" );
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document.write( "    \"pi%2AR%5E2\" - \"pi%2Ar%5E2\" = \"3.14159%2A%289.4%5E2-8.14%5E2%29\" = 69.43 cm^2.\r\n" );
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