document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153295>Question 1153295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the area of the largest circle that can be inscribed in a hexagon of side “h”.<BR>\n" );
document.write( "A.2.356 h2<BR>\n" );
document.write( "B.2.441 h2<BR>\n" );
document.write( "C.3.146 h2<BR>\n" );
document.write( "D.1.786 h2 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775483 by </B><A HREF=/tutors/aboutme.mpl?userid=MathLover1><B>MathLover1(20850)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=MathLover1><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=MathLover1><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775483\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <a  rel=nofollow HREF=\"https://www.imageupload.net/image/Zx8k1\"><IMG STYLE=\"max-width:80%;\" src=\"https://imagehost.imageupload.net/2020/03/02/Untitled-143-300x199.th.png\" alt=\"Untitled-143-300x199.png\" border=\"0\" /></a>\r<BR>\n" );
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document.write( "From the figure, it is clear that, we can divide the regular hexagon into<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+6+ ALIGN=MIDDLE  ALT=\"+6+\"   DISABLED_style= \"max-width:90%; height:auto;\" >identical equilateral triangles.\r<BR>\n" );
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document.write( "We take one triangle<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+OAB ALIGN=MIDDLE  ALT=\"+OAB\"   DISABLED_style= \"max-width:90%; height:auto;\" >, with <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=O ALIGN=MIDDLE  ALT=\"O\"   DISABLED_style= \"max-width:90%; height:auto;\" > as the center of the hexagon or circle, & <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AB ALIGN=MIDDLE  ALT=\"AB\"   DISABLED_style= \"max-width:90%; height:auto;\" > as one side of the hexagon.\r<BR>\n" );
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document.write( "Let <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=M ALIGN=MIDDLE  ALT=\"M\"   DISABLED_style= \"max-width:90%; height:auto;\" > be mid-point of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AB ALIGN=MIDDLE  ALT=\"AB\"   DISABLED_style= \"max-width:90%; height:auto;\" >, <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=OM ALIGN=MIDDLE  ALT=\"OM\"   DISABLED_style= \"max-width:90%; height:auto;\" > would be the perpendicular bisector of <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AB ALIGN=MIDDLE  ALT=\"AB\"   DISABLED_style= \"max-width:90%; height:auto;\" >, angle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=AOM+=+30 ALIGN=MIDDLE  ALT=\"AOM+=+30\"   DISABLED_style= \"max-width:90%; height:auto;\" >° \r<BR>\n" );
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document.write( "Then in right angled triangle <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=OAM ALIGN=MIDDLE  ALT=\"OAM\"   DISABLED_style= \"max-width:90%; height:auto;\" >,side <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=a ALIGN=MIDDLE  ALT=\"a\"   DISABLED_style= \"max-width:90%; height:auto;\" > (in your case is <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h ALIGN=MIDDLE  ALT=\"h\"   DISABLED_style= \"max-width:90%; height:auto;\" >)\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=tan%28x%29+=+tan%2830%29+=+1%2Fsqrt%283%29 ALIGN=MIDDLE  ALT=\"tan%28x%29+=+tan%2830%29+=+1%2Fsqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "So, \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%2F2r+=+1%2Fsqrt%283%29 ALIGN=MIDDLE  ALT=\"h%2F2r+=+1%2Fsqrt%283%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Therefore, \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=r+=+%28h%2Asqrt%283%29%29%2F2 ALIGN=MIDDLE  ALT=\"r+=+%28h%2Asqrt%283%29%29%2F2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "Area of circle is:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=pi%2Ar%5E2 ALIGN=MIDDLE  ALT=\"A+=pi%2Ar%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=pi%2A%28%28h%2Asqrt%283%29%29%2F2%29%5E2 ALIGN=MIDDLE  ALT=\"A+=pi%2A%28%28h%2Asqrt%283%29%29%2F2%29%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=%283%2Api%2F4%29h%5E2 ALIGN=MIDDLE  ALT=\"A+=%283%2Api%2F4%29h%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=2.356.h%5E2 ALIGN=MIDDLE  ALT=\"A+=2.356.h%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
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document.write( "answer: A.<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=2.356h%5E2 ALIGN=MIDDLE  ALT=\"2.356h%5E2\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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