document.write( "Question 1153277: Please help me
\n" ); document.write( "If
\n" ); document.write( "f(x) = 6x2 − x3,
\n" ); document.write( " find f '(1) and use it to find an equation of the tangent line to the curve
\n" ); document.write( "y = 6x2 − x3
\n" ); document.write( " at the point (1, 5).
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Algebra.Com's Answer #775472 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Use \"^\" (shift-6) to denote exponents.

\n" ); document.write( "Your function is y = 6x^2-x^3.

\n" ); document.write( "\"y+=+6x%5E2-x%5E3\"
\n" ); document.write( "\"dy%2Fdx+=+12x-3x%5E2\"

\n" ); document.write( "At x=1, the derivative (slope) is 12(1)-3(1^2) = 12-3 = 9.

\n" ); document.write( "The equation of the tangent line at (1,5) is y = 9x-4.

\n" ); document.write( "A graph, showing the function and the tangent line at (1,5):

\n" ); document.write( "\"graph%28400%2C400%2C-5%2C5%2C-15%2C35%2C6x%5E2-x%5E3%2C9x-4%29\"

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