document.write( "Question 1153217: Teddy watched a spider crawl through an arc of 54 degrees on a disc radius 10 in , how far did the spider crawl? thanks! \n" ); document.write( "
Algebra.Com's Answer #775404 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "The length of an arc, \"s\", is given by:
\n" ); document.write( "
\n" ); document.write( "\"s+=+r%2Atheta\"
\n" ); document.write( "
\n" ); document.write( "where:
\n" ); document.write( "\"s\" = arc length
\n" ); document.write( "\"r\" = radius
\n" ); document.write( "\"theta\" = angle in radians
\n" ); document.write( "
\n" ); document.write( "The radius of the disc is \"r+=+10in\" and the angle the spider crawled through is \"54\"°. We need to convert the angle from degrees to radians.
\n" ); document.write( "There are \"pi\" radians in \"180\"°, so we can set up a proportion to determine the angle \"theta\" in radians:
\n" ); document.write( "
\n" ); document.write( " \"54%2F180=++theta+%2Fpi\"
\n" ); document.write( "\"54pi%2F180=++theta+\"
\n" ); document.write( "\"theta=0.9425+\"radians
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( "\"s+=+10in%2A%280.9425+%29+=+9.43in+\"\r
\n" ); document.write( "\n" ); document.write( "how far did the spider crawl? \r
\n" ); document.write( "\n" ); document.write( "answer is: about \"9.43in+\"\r
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );