document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153117>Question 1153117</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 1.	According to the IRS, for 2014, the average total itemized deductions that were taken was $25,230. This average was based on a sample of 20 individuals that took an itemized deduction. The standard deviation for this sample was $3,200. Assume that the data approximates a normal curve. Find a 98% confidence interval for the true population mean. please show steps with cakculator </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775329 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775329\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the half-interval is a t df=19,0.99*s/sqrt(n)<BR>\n" );
document.write( "=2.539*3200/sqrt(20)=1816.76\r<BR>\n" );
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document.write( "add and subtract from mean<BR>\n" );
document.write( "($23413, $27047)\r<BR>\n" );
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document.write( "Find t by using the table or STAT TESTS 8 (T interval)<BR>\n" );
document.write( "Then put in mean 0, sd sqrt(20)n-20 and .98 for CI<BR>\n" );
document.write( "That is where the 2.539 comes from<BR>\n" );
document.write( "then use T-interval again to get the CI. </SPAN>\n" );
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