document.write( "Question 1153164: 27% of a certain country's voters think that it is too easy to vote in their country. You randomly select 12 likely voters. Find the probability that the number of likely voters who think that it is too easy to vote is (a) exactly three, (b) at least four, (c) less than eight.
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Algebra.Com's Answer #775325 by Boreal(15235) $\"\"$ $\"About$

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This is a binomial with n=12 p=0.27
\n" ); document.write( "for exactly 3, it is 12C3*0.27^3*0.73^9=0.2549\r
\n" ); document.write( "\n" ); document.write( "at least 4, find 0,1,2
\n" ); document.write( "0 is .73^12=0.0229
\n" ); document.write( "1 is 12*.27*.73^11=0.1016
\n" ); document.write( "2 is 66*.27^2*.73^10=0.2068\r
\n" ); document.write( "\n" ); document.write( "The sum of 0,1,2,3 [probabilities above is 0.5862
\n" ); document.write( "So at least 4 is 1-0.5862 or 0.4138\r
\n" ); document.write( "\n" ); document.write( "for 8: prob =0.0040
\n" ); document.write( "for 9: prob=0.0007
\n" ); document.write( "for 10: prob=0.00007 or 0.0001
\n" ); document.write( "11 and 12 are too small to consider
\n" ); document.write( "probability 8 or more is 0.0048\r
\n" ); document.write( "\n" ); document.write( "probability fewer than 8 is the complement or 0.9592 \n" ); document.write( "

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