document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153148>Question 1153148</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The daily revenue of a boutique is normally distribution with a mean of $10,000 and a standard deviation of $2,000. Assume that the boutique works seven days a week. What is the probability that there are two weeks in four non-overlapping weeks that the average daily revenue of the boutique is between $8,500 and $12,000? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775324 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775324\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> I am assuming exactly two weeks<BR>\n" );
document.write( "This is z between (8500-10000)/2000 and (12000-10000)/2000 or z between -0.75 and +1.\r<BR>\n" );
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document.write( "That probability itself is 0.6147<BR>\n" );
document.write( "To have 2 weeks would be 4C2*0.6147^2*0.3853^2, which is the binomial for choosing 2 out of 4 weeks with a certain probability for 2.\r<BR>\n" );
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document.write( "That is 0.3366 </SPAN>\n" );
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