document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153152>Question 1153152</A>: <I><SPAN STYLE=\"word-break: break-all;\"> If angle A and angle B are supplementary angles and angle A is 3 times as large as angle B find the measures of angle A and Angle B </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775317 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775317\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> if the angles are supplementary than their sum is 180 degrees.<BR>\n" );
document.write( "A + B = 180<BR>\n" );
document.write( "if angle A is 3 times as large as angle B, then:<BR>\n" );
document.write( "A = 3B<BR>\n" );
document.write( "equation becomes:<BR>\n" );
document.write( "3B + B = 180<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "4B = 180<BR>\n" );
document.write( "solve for B to get:<BR>\n" );
document.write( "B = 180 / 4 = 45<BR>\n" );
document.write( "angle A is 3 time angle B, therefore angle A is 135 degrees.<BR>\n" );
document.write( "135 + 45 = 180 therefore the angles are supplementary.<BR>\n" );
document.write( "solution is angle A is 135 degrees and angle B is 45 degrees. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );