document.write( "Question 1153131: Hello! I've been trying to solve this problem- it goes as shown: For a particular sequence, each term is the sum of the three preceding terms. If a, b, c, d, e, 0, 1, 2, 3 are consecutive terms of this sequence, what is the value of a + b + c + d + e?\r
\n" ); document.write( "\n" ); document.write( "My attempts to solve this have gone as follows:\r
\n" ); document.write( "\n" ); document.write( "Since the 8th term (2) is the sum of e + 0 + 1, e must be 1, as that would be the only solution to this. I worked backwards from there: 1 = 0 + 1 + d, so d must be 0. This is where my reasoning failed. I thought c was equal to -1, which meant that b must be 2, and a must be -1. However, since the only term preceding b is -1, I thought b must be -1, too. \r
\n" ); document.write( "\n" ); document.write( "Is it wrong of me to think the sequence must start on a? Is it implied that the sequence goes much further backwards?\r
\n" ); document.write( "\n" ); document.write( "Thank you in advance for any and all help! \n" ); document.write( "

Algebra.Com's Answer #775293 by math_helper(2461) $\"\"$ $\"About$

You can put this solution on YOUR website!

\n" ); document.write( "Unless otherwise specified, you are correct to assume the sequence starts at 'a' (so while working backwards, a+b+c=d is the last valid equation you can write).
\r
\n" ); document.write( "\n" ); document.write( "Your answer looks correct: -1,2,-1,0,1,0,1,2,3\r
\n" ); document.write( "\n" ); document.write( " \n" ); document.write( "

\n" );