document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1153062>Question 1153062</A>: <I><SPAN STYLE=\"word-break: break-all;\"> xy=30<BR>\n" );
document.write( "3x+y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775212 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13200)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775212\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "If you are looking for solutions in real numbers, it is easy to quickly determine that there are none through logical reasoning.<br><BR>\n" );
document.write( "(1) The equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=xy=30 ALIGN=MIDDLE  ALT=\"xy=30\"   DISABLED_style= \"max-width:90%; height:auto;\" > tells us that x and y are either both positive or both negative.<br><BR>\n" );
document.write( "(2) Knowing that, the equation <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3x%2By=1 ALIGN=MIDDLE  ALT=\"3x%2By=1\"   DISABLED_style= \"max-width:90%; height:auto;\" > tells us that x and y are both positive, and that both are less than 1.<br><BR>\n" );
document.write( "(3) Logical reasoning then tells us that it is not possible to have a product of 30 using two numbers less than 1.<br><BR>\n" );
document.write( "ANSWER: No solution in real numbers.<br><BR>\n" );
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