document.write( "Question 15668: I have more than one question: 2m+5=m over 5-4, m over 2+3 = m over 5+5,3x+4(x-2=7+x,6(2x+7)=102,x+7=2(x-1), 6(x+2x+1)=12x. \n" ); document.write( "
Algebra.Com's Answer #7752 by pwac(253)\"\" \"About 
You can put this solution on YOUR website!
\"2m%2B5=m%2F%285-4%29\"
\n" ); document.write( "\"2m%2B5=m%2F1\" Anything over one is unchanged,so:
\n" ); document.write( "2m+5=m Sutract m from both sides
\n" ); document.write( "m+5=0 Subtract 5 from both sides gives m=-5\r
\n" ); document.write( "\n" ); document.write( "\"m%2F%282%2B3%29=m%2F%285%2B5%29\"is same as:\"m%2F5=m%2F10\"Multiply both sides by 10 and 5
\n" ); document.write( "to get\"10m=5m\".This is not possible.Have you missed a coefficient of m?\r
\n" ); document.write( "\n" ); document.write( "3x+4(x-2)=7+x Multiply everything in bracket by the 4:
\n" ); document.write( "3x+4x-8=7+x which is 7x-8=7+x Sutract x from both sides
\n" ); document.write( "6x-8=7 Add 8 to both sides to get:
\n" ); document.write( "6x=15 Divide both sides by 6
\n" ); document.write( "\"x=15%2F6=2.5\"\r
\n" ); document.write( "\n" ); document.write( "6(2x+7)=102 Remove bracket by multiplying by the 6
\n" ); document.write( "12x+42=102 Subtract 42 from both sides
\n" ); document.write( "12x=60 Divide both sides by 12
\n" ); document.write( "x=5
\n" ); document.write( "You have the idea by now so try next two yourself.\r
\n" ); document.write( "\n" ); document.write( "Pete
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