document.write( "Question 1153048: The force of attraction between the earth and some object is called the weight of that object. The law of gravitation states, then, that the weight of an object is inversely proportional to the square of its distance from the centre of the earth. If a person weighs 190 lb on the surface of the earth (assume this to be 3960 mi from the centre), how much will he weigh 1800 mi above the surface of the earth?\r
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document.write( "Round your answer to the nearest integer.\r
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document.write( "Weight 1800 mi above the surface = \n" );
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Algebra.Com's Answer #775195 by josgarithmetic(39616)![]() ![]() ![]() You can put this solution on YOUR website! -------------------------------------------------------------- \n" ); document.write( "..., the weight of an object is inversely proportional to the square of its distance from the centre of the earth. \n" ); document.write( "-------------------------------------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "d, distance from center \n" ); document.write( "w, weight of object \n" ); document.write( "k, variation constant\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( "-\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------ \n" ); document.write( " If a person weighs 190 lb on the surface of the earth (assume this to be 3960 mi from the centre),... \n" ); document.write( "-------------------------------\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Model equation is \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Your question has \n" ); document.write( " |