document.write( "Question 1152999: A wooden artifact from an archaeological dig contains 80 percent of the Carbon-14 that is present in living trees. To the nearest year, about how many years old is the artifact? (The half-life of Carbon-14 is 5730 years.)
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Algebra.Com's Answer #775165 by ankor@dixie-net.com(22740)\"\" \"About 
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A wooden artifact from an archaeological dig contains 80 percent of the Carbon-14 that is present in living trees.
\n" ); document.write( "To the nearest year, about how many years old is the artifact?
\n" ); document.write( " (The half-life of Carbon-14 is 5730 years.)
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\n" ); document.write( "The radiation decay formula
\n" ); document.write( "\"A+=+Ao%2A2%5E%28-t%2Fh%29\", where
\n" ); document.write( "A = resulting amt after t time
\n" ); document.write( "Ao = initial amt of the substance
\n" ); document.write( "t = time of decay
\n" ); document.write( "h = half-life of substance
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\n" ); document.write( "let Ao = 10 and A = 8
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\n" ); document.write( "\"10%2A2%5E%28-t%2F5730%29+=+8\"; (t is the numerator)
\n" ); document.write( "\"2%5E%28-t%2F5730%29+=+8%2F10\"
\n" ); document.write( "\"2%5E%28-t%2F5730%29+=+.8\"
\n" ); document.write( "using natural logs
\n" ); document.write( "\"-t%2F5730\"ln(2) = ln(.8)
\n" ); document.write( "\"%28-t%2F5730%29+=+ln%28.8%29%2Fln%282%29\"
\n" ); document.write( "using your calc
\n" ); document.write( "\"%28-t%2F5730%29+=+-.3219\"
\n" ); document.write( "t = -5730 * -3219
\n" ); document.write( "t = 1845 yrs\r
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