document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152991>Question 1152991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A food safety guideline is that the mercury in fish should be below 1 part per million​ (ppm). Listed below are the amounts of mercury​ (ppm) found in tuna sushi sampled at different stores in a major city. Construct a 95​% confidence interval estimate of the mean amount of mercury in the population. Does it appear that there is too much mercury in tuna​ sushi?<BR>\n" );
document.write( "0.58  0.70  0.09  0.98  1.31  0.57  0.96   \r<BR>\n" );
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document.write( "What is the confidence interval estimate of the population mean mu​?<BR>\n" );
document.write( "(?) ppm < mu < (?) ppm<BR>\n" );
document.write( "​(Round to three decimal places as​ needed.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775143 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775143\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Get 1 variable stats from this<BR>\n" );
document.write( "mean  is 0.741<BR>\n" );
document.write( "s is 0.389<BR>\n" );
document.write( "n=7<BR>\n" );
document.write( "do a 95% CI which is mean +/- t df=6, 0.975 s/ sqrt(n)<BR>\n" );
document.write( "This yields 0.741+/- 2.447*0.389/sqrt(7)=0.741+/-0.360<BR>\n" );
document.write( "95% CI is (0.381, 1.101)<BR>\n" );
document.write( "Since the critical value of 1 ppm is IN the interval, it is entirely possible that the true value is that or even more, so yes, there is evidence to support the claim that there is too much mercury in the sushi. </SPAN>\n" );
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