document.write( "Question 1152980: Divide 15 into two parts such that when the larger is divided by 3 and the smaller is divided by 2 the quotients are equal \n" ); document.write( "
Algebra.Com's Answer #775121 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "let larger part be \"x\" and smaller part \"y\"\r
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\n" ); document.write( "\n" ); document.write( "\"x%2By=15\"
\n" ); document.write( "\"x=15-y\".........eq.1\r
\n" ); document.write( "\n" ); document.write( "when the larger is divided by \"3\" and the smaller is divided by \"2+\" the quotients are equal:\r
\n" ); document.write( "\n" ); document.write( "\"x%2F3=y%2F2\".......solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"x=3y%2F2\".......eq.2\r
\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have\r
\n" ); document.write( "\n" ); document.write( "\"15-y=3y%2F2\"........solve for \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"30-2y=3y\"\r
\n" ); document.write( "\n" ); document.write( "\"30=3y%2B2y\"\r
\n" ); document.write( "\n" ); document.write( "\"5y=30\"\r
\n" ); document.write( "\n" ); document.write( "\"y=6\"\r
\n" ); document.write( "\n" ); document.write( "then\r
\n" ); document.write( "\n" ); document.write( "\"x=15-y\".........eq.1
\n" ); document.write( "\"x=15-6\"
\n" ); document.write( "\"x=9\"\r
\n" ); document.write( "\n" ); document.write( " two parts are \"9\" and \"6\"\r
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