document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1152966>Question 1152966</A>: <I><SPAN STYLE=\"word-break: break-all;\"> you invested $5000 between two accounts paying 7% and 9% annual interest, respectively. If the total interest earned for the year was $390 how much was invest at each rate?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #775111 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13206)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=775111\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a very different non-algebraic way for solving many kinds of problems similar to this one.<br><BR>\n" );
document.write( "All $5000 invested at 7% would yield $350 interest; all at 9% would yield $450 interest.<br><BR>\n" );
document.write( "Use any method you want to determine that the actual interest of $390 is \"40/100 = 2/5 of the way from $350 to $450\".<br><BR>\n" );
document.write( "That means 2/5 of the money was invested at the higher rate.<br><BR>\n" );
document.write( "ANSWER: 2/5 of the $5000, or $2000, at 9%; $3000 at 7%<br><BR>\n" );
document.write( "CHECK: .09(2000)+.07(3000) = 180+210 = 390<br><BR>\n" );
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